3x^2-33=30x

Solution for 3x^2-33=30x equation:

3x^2-33=30x

We move all terms to the left:

3x^2-33-(30x)=0

a = 3; b = -30; c = -33;
Δ = b2-4ac
Δ = -302-4·3·(-33)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-36}{2*3}=\frac{-6}{6}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+36}{2*3}=\frac{66}{6}
=11
$